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Jose R Ortiz Ubarri 8 роки тому
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@@ -265,12 +265,12 @@ In the introduction to the topic of functions you saw that in mathematics and in
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 3. Open the file `main.cpp` (in Sources). Study the `illustration` function and how to call it from the `main` function. Note that the variables `argValue` and `argRef`are initialized to 0 and that the function call for `illustration` makes a pass by value of `argValue` and a pass by reference of `argRef`. Also note that the corresponding parameters in `illustration` are assigned a value of 1.
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-        void illustration(int paramValue, int &paramRef) {
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-            paramValue = 1;
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-            paramRef = 1;
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-            cout << endl << "The content of paramValue is: " << paramValue << endl
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-                 << "The content of paramRef is: " << paramRef << endl;
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-        }
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+      void illustration(int paramValue, int &paramRef) {
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+        paramValue = 1;
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+        paramRef = 1;
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+        cout << endl << "The content of paramValue is: " << paramValue << endl
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+             << "The content of paramRef is: " << paramRef << endl;
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+      }
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 4. Execute the program and observe what is displayed in the window `Application Output`. Notice the difference between the content of the variables `argValue` and `argRef` despite the fact that both had the same initial value, and that `paramValue` and `paramRef` were assigned the same value. Explain why the content of `argValor` does not change, while the content of `argRef` changes from 0 to 1.
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