README-en.md edited online with Bitbucket

README-en.md

@@ -57,7 +57,7 @@ The drawing will be on a grid. The tools will be used by clicking any cell in th
 	**Figure 1.**  The image shows the direction in which the coordinates are ordered in `Qt` images.
 
 
-* When we want to insert two-dimensional data (like the entries of a grid that has coordinates in $x$ and $y$) in an one-dimensional array we use a formula to convert every coordinate $(x,y)$ to an index $i$ of the array. For every point with coordinates $(x,y)$ in the grid, we evaluate $i=(number-of-columns)*y+x$, where `number-of-columns` represents the width of the two-dimensional array, and the result $i$ will be the index of the one-dimensional array that corresponds to the point with coordinates $(x,y)$ in the grid. For example, the index $i$ that corresponds to the point $(1,2)$ in the grid of width $5$ is $i=(5)*2+1=11$.
+* When we want to insert two-dimensional data (like the entries of a grid that has coordinates in $$x$$ and $$y$$) in an one-dimensional array we use a formula to convert every coordinate $$(x,y)$$ to an index $$i$$ of the array. For every point with coordinates $$(x,y)$$ in the grid, we evaluate $$i=(number-of-columns)*y+x$$, where `number-of-columns` represents the width of the two-dimensional array, and the result $$i$$ will be the index of the one-dimensional array that corresponds to the point with coordinates $$(x,y)$$ in the grid. For example, the index $$i$$ that corresponds to the point $$(1,2)$$ in the grid of width $$5$$ is $$i=(5)*2+1=11$$.
 
 
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@@ -69,15 +69,15 @@ The drawing will be on a grid. The tools will be used by clicking any cell in th
 
 In this project, you will need to use the following `QtGlobal` functions for the implementation of the circle. 
 
-* `int qFloor(qreal v)` // Returns the “floor” value $v$.
-* `qreal qSqrt(qreal v)` // Returns the square root of the value $v$.
-* `qreal qPow(qreal x, qreal y)` // Returns the value of $x$ to the power of $y$.
+* `int qFloor(qreal v)` // Returns the “floor” value $$v$$.
+* `qreal qSqrt(qreal v)` // Returns the square root of the value $$v$$.
+* `qreal qPow(qreal x, qreal y)` // Returns the value of $x$ to the power of $$y$$.
 
 In addition, you will need to use the function that paints the grid:
 
-* `void switchOn(int x, int y, const QColor& color);` // Paints the cell $(x,y)$ with the given color. (You don't have to worry about `QColor` because it is passed by the function's parameter)
+* `void switchOn(int x, int y, const QColor& color);` // Paints the cell $$(x,y)$$ with the given color. (You don't have to worry about `QColor` because it is passed by the function's parameter)
 
-Although the archive `tools.cpp` is not visible, there is an array called `mColors`that contains the color of all the cells in the grid. This will help you know which color is in the cell: `mColors[columns * y + x]`. Note that the index of the array is calculated using the conversion explained above that changes the coordinates $(x,y)$ to an index. 
+Although the archive `tools.cpp` is not visible, there is an array called `mColors`that contains the color of all the cells in the grid. This will help you know which color is in the cell: `mColors[columns * y + x]`. Note that the index of the array is calculated using the conversion explained above that changes the coordinates $$(x,y)$$ to an index. 
 
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@@ -172,7 +172,7 @@ Now, you will implement the functionality to draw squares, circles and triangles
 
 #### 2a: Squares 
 
-For the squares, the easiest way to think of it is as if they were onions! A square of size 1 is simply the cell clicked by the user. A square of size 2 is the cell clicked by the user, covered by a layer of cells of size 1, and so on. In other words, a square of size $n$ will have height = width = $2n-1$.
+For the squares, the easiest way to think of it is as if they were onions! A square of size 1 is simply the cell clicked by the user. A square of size 2 is the cell clicked by the user, covered by a layer of cells of size 1, and so on. In other words, a square of size $$n$$ will have height = width = $$2n-1$$.
 
 
 
@@ -182,7 +182,7 @@ For the squares, the easiest way to think of it is as if they were onions! A squ
 
 #### 2b: Triangles
 
-The triangle button produces an **isosceles** triangle as it is shown in Figure 7. For a selected size $n$, the size of the base will be $2n + 1$. The height should be $n+1$.
+The triangle button produces an **isosceles** triangle as it is shown in Figure 7. For a selected size $$n$$, the size of the base will be $$2n + 1$$. The height should be $n+1$.
 
 
 ![](images/triangles.png)
@@ -201,9 +201,9 @@ Congratulations! You got to the most difficult part: circles! Here you’ll need
 
 **Help Producing Circles:**
 
-First of all, you need to understand that the terms associated with a circle that has an equation: $x^2+y^2=r^2$. For example, consider a circle with radius $r=1$. The equation $x^2+y^2=1$ tells us that every point $(x,y)$ that satisfies the equation is a point in the circle’s *circumference*. The expression for a *filled* circle is : $x^2 + y^2 <=r^2$. A filled circle, of radius $r=1$ has the expression  $x^2 + y^2 <= 1$, which says that every point $(x,y)$ that satisfies $x^2 + y^2 <= 1$ is a point in a filled circle.
+First of all, you need to understand that the terms associated with a circle that has an equation: $$x^2+y^2=r^2$$. For example, consider a circle with radius $$r=1$$. The equation $$x^2+y^2=1$$ tells us that every point $$(x,y)$$ that satisfies the equation is a point in the circle’s *circumference*. The expression for a *filled* circle is : $$x^2 + y^2 <=r^2$$. A filled circle, of radius $$r=1$$ has the expression  $$x^2 + y^2 <= 1$$, which says that every point $$(x,y)$$ that satisfies $$x^2 + y^2 <= 1$$ is a point in a filled circle.
 
-How do we produce a circle? One way would be to generate all the points near the center of the circle and determine if those satisfy the expression $x^2 + y^2 <= r^2$. For example, we can try all of the points that are in the square of size $2r+1$. For the circle of radius $r=2$ we would have to generate the following points and prove them in the expression $x^2 + y^2 <=4$:
+How do we produce a circle? One way would be to generate all the points near the center of the circle and determine if those satisfy the expression $$x^2 + y^2 <= r^2$$. For example, we can try all of the points that are in the square of size $$2r+1$$. For the circle of radius $$r=2$$ we would have to generate the following points and prove them in the expression $$x^2 + y^2 <=4$$:
 
 
 ````
@@ -214,7 +214,7 @@ How do we produce a circle? One way would be to generate all the points near the
 (-2,-2) (-1,-2) ( 0,-2) ( 1,-2) ( 2,-2)
 ```` 
 
-In this case, only the points that are shown below satisfy the expression  $x^2 + y^2 <=4$.
+In this case, only the points that are shown below satisfy the expression  $$x^2 + y^2 <=4$$.
 
 
 ````